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dN / dt =- kN2.
where 2 is supersubscribe
derive the solution.
N(t)=No (1+ t/T) -1,where o is subscribe and -1
is B=C Io(r a) +D Ko(r/a)
In our particular case the solution is Ko.
How we get
B= (h/2 phi a^2) Ko(r/a)
Where h= magnetic flux= Integral B d2r. Phi=3.14. And a=(m/meu. n e^2) 1/2