Answer to Question #3220 in Mechanics | Relativity for ZherVin

Question #3220
Find the force F which when applied at an horizontal angle of 15 degrees to the center of a wheel of radius R and weight W will pull it over a step of height y <r
Expert's answer
We assume that force applied at an horizontal angle of 15 degrees up, otherwise it wouldn't pull the wheel over a step, it would pull it down. This is a torque problem, with the pivot point being at the corner of the step that the wheel will rotate around to get on top of the step. The applied force must provide a torque greater than the torque provided by the weight.
So the torque provided by force
F: F*cos(15)*r > mg*r - the torque provided by the weight when when center of the wheel is at distance r from the vertical
edge of the step
F > mg/cos(15), mg = W
F > W/cos(15)

F_min = W/cos(15)

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be the first!

Leave a comment

Ask Your question

New on Blog