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Solution a empty glass test tube is floted vertically in water depth 5 cm. Now on introducing a8cm liquid column in the tube its depth water is furthe increase by 4 cm now if the empty test tube is allow to float vertically in liquid 5cm of the tube is seen in air, find the total length of the tube

"A UNIFORM TOY OF CONSTANT DENSITY IS MADE BY MOUNTING A CONE OF HEIGHT H AND RADIUS R ON A HEMISPHERE OF RADIUS R.FIND RATIO H/R IF CENTER OF MASS OF TOYIS TO TOY IS TO LIE AT THE CENTER OF COMMON BASE."

A car starts from rest and rolls down a hill. The height of the hill is .3 km and the distance travelled by the car is 4.8 km. What is the acceleration?

A car goes at a constant 16 m/s up a hill. the frictional force is 500N. The height of the hill is .3 km and it the car travels a distance of 4.8 km. What is the work done in order to get to the top of the hill.?

A 6.9 kg bowling ball is initially at rest. If a 13 N force acts on it for 0.14 s, what is the final velocity of the bowling ball?

In an attempt to escape his island, Gilligan builds a raft and sets to sea. The wind shifts a great deal during the day, and he is blown along the following straight lines:

2.5 km 45° north of west; then

4.70 km 60° south of east; then

5.1 km straight east; then

7.2 km 55° south of west; and finally

2.8 km 10° north of east.

2.5 km 45° north of west; then

4.70 km 60° south of east; then

5.1 km straight east; then

7.2 km 55° south of west; and finally

2.8 km 10° north of east.

Consider earth as a sphere of radius 6400km and time period of rotation 24 hour, estimate the centripetal acceleration on a person at

1. The equator

2. At a latitude ø from the earths centre

1. The equator

2. At a latitude ø from the earths centre

At what velocity (m/s) must a 28.7 kg object be moving in order to possess a kinetic energy of 1.03 J?

The initial velocity of a car (m = 1000. kg) moving along a straight, horizontal road equals 72 km/h. What minimal time and distance are needed to stop the car if the static friction coefficient between the tires and the road equals 0.50?

how can we find average speed from the table ?