Answer on Mechanics | Relativity Question for ZherVin
T = 2π/ω = 2π√(I/gML),
where I is the moment of inertia of a uniform stick of mass M and length L is pivoted at one end.
T = 2π/ω = 2π√(I/gML) = 2π√(((ML2)/3)/gML) = 2π√(L/3g).
The period of oscillation if the stick is pivoted about point P a distance x from the center of mass
And we have
T = 2π/ω = 2π√(I/gML) = 2π√(((ML2)/12 + Mx2)/gML) = 2π√((L2/12+x2)/gL).
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