57 380
Assignments Done
Successfully Done
In February 2018
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Mechanics | Relativity Question for zizi

Question #3181
A basketball player is standing on the floor 10.0 m from the basket .The height of the basket is 3.05 m and he shoots the ball at 40.0 angle with the horizantal from the height of 2.00 m .
A- What is the acceleration of the of the basketball at the heights point in its trajectory ?
B- At what speed must the player throw the basketball so that the ball goes through the hoop without striking the bachboard?
Expert's answer
First, establish a rectangualr coordinate system, with the origin at say 2m above the floor and 10m from the hoop.

Initial position: (xi, yi) = (0,2)

Final position: (xf, yf) = (10, 1.05) ...note that yf is 1.05 m above the origin defined above.

Launch angle is 40 deg above horizontal.

To find the initial speed, we find the components of the initial velocity, whcih we write

Vix = Vi cos 40 Viy = Vi sin 40

horizontal Velocity = V*Cosθ
If T is the total time of flight, and the basket is 10m away then you know that V*Cosθ*T = 10m

time required to reach the maximum height
Initial velocity/g = V*Sinθ/g = T1

Now T1 is only the part of the problem, because Total time = Time to rise (T1) plus time to fall down(T2).

Max height :(V*Sinθ)2 = 2gH
(Remember H is 2m higher than the ground.)
How long to drop from max height?
(H - 1.02) = 1/2 g* T22
(The 1.02 is the difference in height above the release point.)
1.05=10tan40 - (490/v2(cos40)2)
v2((cos40)2*10tan40) - 490 = v2((cos40)2)
v2((cos40)2*10tan40) - v2((cos40)2) = 490
v2(4.337215) = 490
v = (490/4.337215)0.5
v = 10.66m/s
Now acceleration a = -g, where g = 9.81 m/s2 is the gravity acceleration which is directed verticaly to the ground, horizonlal component of acceleration=0.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question