Answer to Question #3131 in Mechanics | Relativity for zizi

Question #3131
A stone is thrown from the ground upward with an initial velocity of 20 m/s a- At what time the stone will reach the maximum height? b- What is the maximum height the stone can reach ? c- What is the height of the stone from the ground after 3 seconds ? I solved ( A) and ( B) and I need answer for part ( C ) Answer A- Vf = Vi + gt 0 = 20 + ( 9.8 m/s2) t 20 + 9.8t = 0 9.8 t = -20 so t = -20/9.8 m/s^2 = 2.04 second B- Vf^2 = Vi^2 + 2g ( Xf – Xi) (0)^2 = (20)^2 + 2 ( -9.8 m/s^2) ( Xf – 0) (20)^2 + 2 (-9.8 m/s^2)(Xf) = 0 400 - 19.6 (Xf) = 0 -19.6 Xf = -400 So Xf = - 400/ -19.6 = 20.4 m
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Expert's answer
2011-06-14T04:35:42-0400
c) use the formula: h = h0 + v0t - gt2/2.
for h0 = 0, v0 = 20 m/s, g = 10 m/s2, t = 3s:
h(t = 3) = 20*3 - 10*9/2 = 15 m.

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