Answer to Question #3212 in Mechanics | Relativity for Bella
Then The height H=S*sin(30)=S/2
Initial mechanical energy P=potencial
energy = m*g*H=m*g*S/2 = 0.1*9.81*S/2 = 0.49*S
Total energy when the cart is down E = K+A(F) where A(F)- work of friction force
Also P = E = K+A(F) due to conservation of energy law
Kinetical energy K=m*v2/2=0.1*9/2=0.45
Hence A(F) = 0.49S-0.45 - this value denotes how much mechanical energy is lost
Also A(F) = F*S
Hence friction force is F=(0.49S-0.45)/S
If the cart collides with a second cart, of mass 200g, at the bottom of the ramp and sticks then due to the Law of impuls conservation: m*V=(m+M)*v1
where m - mass of the first cart, M-mass of the second cart
v1=*0.1*3/0.3=*1 m/s - velocity of twa carts after collision.
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!