Answer to Question #16287 in Mechanics | Relativity for Jazmine Santiago
1. a car displaced 45°north of east by 10.0km (north and east)
1. a car displaced 45њnorth of east by 10.0km (north and east)
The car's north and east components are
N = 10[km]*sin(π/4) = 10/√2 [km],
E = 10[km]*cos(π/4) = 10/√2 [km].
So, the car's coordinates are (10/√2, 10/√2).
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!