Question #16259

a particle is thrown vertically upwars. its velocity at half of the height is 10m/s.what is the mximum height attained by it ?

Expert's answer

Let initial velocity is U and maximum height is h.

At maximum height velocity will be zero:

0 =U^{2} -2gh

U^{2} =2gh

Now given velocity is = 10m/sec at height h/2

so 10^{2} = U^{2} -2gh/2

100 =2gh -gh

h = 100/10

h =10 m

At maximum height velocity will be zero:

0 =U

U

Now given velocity is = 10m/sec at height h/2

so 10

100 =2gh -gh

h = 100/10

h =10 m

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