A lift of mass 3000Kg is supported by a steel cable of diameter 20mm. The maximum acceleration of the lift is 2.5ms/xy-2. Calculate
a) prove that the maximum tension in the cable is 37KN
b) prove that the maximum stress in the cable is 120MPa
c) prove that the maximum strain in the cable is 5.9*10/xy-4. [E for steel = 200GPa]

## Comments

## Leave a comment