A person standing at the edge of a cliff kicks a stone over the edge with a speed of 18m/s . The cliff is 52m above the water. How long does it take for the stone to fall to the water? With what speed does it strike the water?
The initial horizontal component of velocity doesn't affect the falling time. We know that
H = gT²/2,
T = √(2H/g) = √(2*52[m]/9.8[m/s²]) ≈ 3.3[s].
The vertical speed component of a stone at the moment of landing will be