Answer on Mechanics | Relativity Question for Alexandra
H = gT²/2,
T = √(2H/g) = √(2*52[m]/9.8[m/s²]) ≈ 3.3[s].
The vertical speed component of a stone at the moment of landing will be
V(vertical) = gT = 9.8[m/s²]*3.3[s] = 32.34[m/s]
and the magnitude of velocity
V = √((V(vertical))² + (V(horizontal))²) = √((18[m/s])² + (32.34[m/s])²) = 37.0[m/s].
So, it will take about 3.3 seconds the stone to fall down and it will strike water with the speed of 37.0 m/s.
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