A force of 340 N is applied horizontally to a wooden crate in order to displace it 39.1 m across a level floor at a constant velocity. As a result of this work the crate’s internal energy is increased by an amount equal to 15 percent of the crate’s initial internal energy. Calculate the initial internal energy of the crate.
Answer in units of J.
1
Expert's answer
2011-02-09T07:01:59-0500
Denote the initial internal energy as U. The work done by a force is A = FS = 340[N]39.1[m] = 13294J and equal to 15 percents of the internal energy: A = 0.15U. Thus U = A/0.15 = 13294/0.15 = 88626.7 J.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
Finding a professional expert in "partial differential equations" in the advanced level is difficult.
You can find this expert in "Assignmentexpert.com" with confidence.
Exceptional experts! I appreciate your help. God bless you!
Comments
Leave a comment