Question #1504

The density of gasoline is 730 kg/m3 at 0 degrees C. One gallon of gasoline occupies 0.0038 m^3.
Gasoline’s volume expansion coefficient is 0.00096 degrees C^−1. How many extra kilograms of gasoline are obtained when fifteen gallons of gasoline are bought at 0 degrees C rather than at 18 degrees C (temperature at the filling station)? Answer in units of kg.

Expert's answer

The volume of fifteen gallons is

V(T=0) = 15 *0.0038 = 0.057 m^{3}

The volume expansion of the gasoline while heating from 0C to 18C:

Δ V = V * α * ΔT = 0.0.057 * 0.00096 * (18-0) = 0.00098496 m^{3}

The mass of gasoline in this extra volume would be

m = 0.00098496[m^{3}] * 730 [kg/m^{3}] = 0.719 kg

V(T=0) = 15 *0.0038 = 0.057 m

The volume expansion of the gasoline while heating from 0C to 18C:

Δ V = V * α * ΔT = 0.0.057 * 0.00096 * (18-0) = 0.00098496 m

The mass of gasoline in this extra volume would be

m = 0.00098496[m

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