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Answer to Question #1470 in Mechanics | Relativity for Gabi

Question #1470
What is the minimum speed of a roller coaster at the top of a 39.0 meter tall vertical loop if the passengers are "weightless" at that point?
Expert's answer
In the top point of the motion the centripetal acceleration should be equal to the gravitation acceletation:
g = V2/R
Thus
V = √(gR) = √(10*39) = 19.75 m/s

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