Question #1470

What is the minimum speed of a roller coaster at the top of a 39.0 meter tall vertical loop if the passengers are "weightless" at that point?

Expert's answer

In the top point of the motion the centripetal acceleration should be equal to the gravitation acceletation:

g = V2/R

Thus

V = √(gR) = √(10*39) = 19.75 m/s

g = V2/R

Thus

V = √(gR) = √(10*39) = 19.75 m/s

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