Question #1458

A car moving westward along a straight, level road increases its velocity uniformly from +19 m/s to +35 m/s in 10.2 s.How far did it move while accelerating? Answer in units of m.

Expert's answer

According to the equations of the motion

V=V_{0} + at

x = x_{0} +V_{0}t +at^{2}/2

Thus

a = (V-V_{0})/t = (35-19)/10.2 = 1.57 m/s2

x = 0 + 19*10.2 + 1.57*10.2^{2}/2 = 245.47 m.

**Answer: 245.47 m.**

V=V

x = x

Thus

a = (V-V

x = 0 + 19*10.2 + 1.57*10.2

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