Question #1474

Metabolizing a candy bar releases about 10^6 joules. How fast must the candy bar travel to have the same 10^6 joules in kinetic energy? The mass of the candy bar is 0.2 kilograms.

Expert's answer

The kinetic energy is

K = mV2/2

Thus

V = √(2*K/m) = √(2*106/0.2) = 2 √(gR) = √(10*39) = 19.75 m/s

K = mV2/2

Thus

V = √(2*K/m) = √(2*106/0.2) = 2 √(gR) = √(10*39) = 19.75 m/s

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