61 724
Assignments Done
97,8%
Successfully Done
In May 2018

Answer to Question #20839 in Electric Circuits for Leandra

Question #20839
A force of 38.0 N accelerates a 5.0-kg block at 5.7 m/s2 along a horizontal surface; how large is the friction force and what is the coefficient of friction?
Expert's answer
ma=F-Ffr
Ffr=F-ma=38-5.0*5.7=9.5 N& --the friction force
mu - the coefficient of friction
mu = Ffr/N
N=mg
mu = Ffr/mg=9.5/(5*10)=0.19

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be first!

Leave a comment

Ask Your question

Submit
Privacy policy Terms and Conditions