Answer to Question #20380 in Electric Circuits for uyuyuyuy
The area of the cross-section of the aorta of radius 1 cm is
S = π·(1[cm])² = π[cm²].
We'll take into account that
5[l] = 5·10³[cm³].
Therefore, the flow rate is
F = 5[l/min] = 5·10³[cm³/min]
and so the average velocity of the blood is
V = F/S = 5·10³[cm³/min] / (π[cm²]) ≈ 1591.55 [cm/min].
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