Question #20837

A 250-kg crate is pushed horizontally with a force of 720 N. If the coefficient of friction is 0.20, calculate the acceleration of the crate.

Expert's answer

F=ma => Newton's law

F=mg - gravity force

F=nmg - friction force

F-ma=nmg

720-250a=0.2*250*10=500

250a=220

a=22/25=0.88 m/s^2

F=mg - gravity force

F=nmg - friction force

F-ma=nmg

720-250a=0.2*250*10=500

250a=220

a=22/25=0.88 m/s^2

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