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# Answer to Question #20241 in Electric Circuits for Miyia

Question #20241
A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. What distance has the spaceship covered after 12.0 seconds?
1
2012-12-10T12:02:38-0500
A spaceship moving with an initial velocity of 58.0 meters/second experiences a uniform acceleration and attains a final velocity of 153 meters/second. What distance has the spaceship covered after 12.0 seconds?

Let's find the time the spaceship needs to obtain velocity of 153 meters/second:

T = (153[m/s] - 58[m/s])/1[m/s&sup2;] = 95[s].

As 12 seconds is less then 95 seconds, then the distance covered by the spaceship after 12.0 seconds from the initial point is

D = 58.0[m/s] * 12.0[s] + 1[m/s&sup2;] * (12.0[s])&sup2; / 2 = 768 [m].

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