57 484
Assignments Done
Successfully Done
In February 2018
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Calculus Question for Bujju

Question #1690
Find an equation of the tangent line to the curve at the point (1, 1).
y = ln (xex2)
Expert's answer
Let's find the first derivation of the function:
f' = (xex^2)'/(xex^2) = (1+x2)/x
The equation of the tangent line can be written as follows:
y = f(x0) + f'(x0) (x-x0)
In our case:
y = ln (1*e) + (1 + 12)/1 * (x-1) = 1 + 2(x-1) = 2x -1
y = 2x-1

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!


No comments. Be first!

Leave a comment

Ask Your question