# Answer on Calculus Question for Abhilash

Question #1686

Differentiate the function.

y = 2x log7(√x)

y = 2x log7(√x)

Expert's answer

y' = 2 log

_{7}(√x) + 2x *(log_{7}(√x))' = log_{7}(x) + 2x* 1/(ln7 *√x) * 1/(2√x) = log_{7}(x) + 1/ln7 = log_{7}(x) + log_{7}(e) = log 7 (xe)Need a fast expert's response?

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