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Answer to Question #1686 in Calculus for Abhilash

Question #1686
Differentiate the function.
y = 2x log7(√x)
Expert's answer
y' = 2 log7(√x) + 2x *(log7(√x))' = log7(x) + 2x* 1/(ln7 *√x) * 1/(2√x) = log7(x) + 1/ln7 = log7(x) + log7(e) = log 7 (xe)

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