Answer to Question #1686 in Calculus for Abhilash

Question #1686

Differentiate the function.
y = 2x log7(√x)

Expert's answer

y' = 2 log₇(√x) + 2x *(log₇(√x))' = log₇(x) + 2x* 1/(ln7 *√x) * 1/(2√x) = log₇(x) + 1/ln7 = log₇(x) + log₇(e) = log 7 (xe)

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