Answer to Question #1688 in Calculus for Abhilash
y = sqrt(x)e^x^2(x^2 + 3)^5
= ex^2(x2+3)4 (1/(2√x)(x2+3) + 2x3√x + 6x√x + 10x√x) = ex^2(x2+3)4(1/2 * x√x +6x√x + 10x√x + 3/(2√x) + 2x3√x) =
= ex^2(x2+3)4 (16.5x√x + 3/(2√x) + 2x3√x)
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