# Answer to Question #1682 in Calculus for Abhilash

Differentiate the function.f(x) = log[sub]9[/sub](xe[sup]x[/sup])

f'(x) = [(xe^{x})ln9]^{-1}* (xe^{x})' = e^{x}(1 +x)* [(xe^{x})ln9]^{-1}= (1+x)/(x ln9)

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Assignment Expert28.02.11, 12:54You are always welcome.

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