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The original function used to model the cost of producing x PortaBoys Game Systems was

C(x) = 80x + 150.

While developing their newest game, Sasquatch Attack!, the makers of the PortaBoy revised their cost function using a cubic polynomial. The new cost of producing x PortaBoys is given by

C(x) = .03x3 − 4.5x2 + 224x + 250.

Market research indicates that the demand function

p(x) = −1.5x + 250

remains unchanged. Find the production level x that maximizes the profit made by producing and selling x PortaBoys.

C(x) = 80x + 150.

While developing their newest game, Sasquatch Attack!, the makers of the PortaBoy revised their cost function using a cubic polynomial. The new cost of producing x PortaBoys is given by

C(x) = .03x3 − 4.5x2 + 224x + 250.

Market research indicates that the demand function

p(x) = −1.5x + 250

remains unchanged. Find the production level x that maximizes the profit made by producing and selling x PortaBoys.

Show that the function f(x) = x–4 + cos(–2x) is even, odd, or neither. algebraically

1. Integral of sin squared 2x cos raised to 4 2x dx

2. Interal of cot raised to 5 x dx

2. Interal of cot raised to 5 x dx

r=a+b cos (phi), trace the curve

f(x)=x^3+3, a=6. Evaluate using f'(a)= lim h->0 f(a-h)-f(a)/h

Confirm that f and g are inverses by showing that f(g(x))=x and g(f(x))=x. F(x)=x^2 -3 ANS g(x)= square root 3 + x

Xsiny=sinp+y

the period of a compound pendulum is given by P = 2\pi sqrt((H² + K²)/(GH)) . express k in terms of p,h andg taking \pi ²as20

definite integral of √{x}dx ,where {x} is the fractional part of x and upper limit of the function is 100 and lower limit of the function is 0.given answer of this question is 2000/3

Multiplies of Lagrange’s method.

1.Z(x+y)p+z(x-y)q=x2+y2

2.x(y2-z2)q-y(z2+x2)q=z(x2+y2)

3.x(y-z)p+y(z-x)q=z(x-y)

4.x2(y-z)p+y2(z-x)q=z2(x-y)

1.Z(x+y)p+z(x-y)q=x2+y2

2.x(y2-z2)q-y(z2+x2)q=z(x2+y2)

3.x(y-z)p+y(z-x)q=z(x-y)

4.x2(y-z)p+y2(z-x)q=z2(x-y)