# Answer to Question #1687 in Calculus for Abhilash

Find f '(1).
f(x) = (ln(x)) / x^9

1
2011-02-28T05:16:44-0500

f'(x) = 1/x * 1/x^{9} - 9 ln(x)/x^{10} = 1/x^{10 }(1- 9ln(x))

f'(x) = 1/1^{10} (1 - 9 ln(1)) = 1 (1-0) = 1

Need a fast expert's response?

Submit order
and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment