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Question #1687

Find f '(1).
f(x) = (ln(x)) / x^9

Expert's answer

f'(x) = 1/x * 1/x^{9} - 9 ln(x)/x^{10} = 1/x^{10 }(1- 9ln(x))

f'(x) = 1/1^{10} (1 - 9 ln(1)) = 1 (1-0) = 1

f'(x) = 1/1

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