# Answer to Question #1687 in Calculus for Abhilash

Question #1687

Find f '(1).

f(x) = (ln(x)) / x^9

f(x) = (ln(x)) / x^9

Expert's answer

f'(x) = 1/x * 1/x

f'(x) = 1/1

^{9}- 9 ln(x)/x^{10}= 1/x^{10 }(1- 9ln(x))f'(x) = 1/1

^{10}(1 - 9 ln(1)) = 1 (1-0) = 1Need a fast expert's response?

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