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Answer to Question #1687 in Calculus for Abhilash

Question #1687
Find f '(1).
f(x) = (ln(x)) / x^9
Expert's answer
f'(x) = 1/x * 1/x9 - 9 ln(x)/x10 = 1/x10 (1- 9ln(x))
f'(x) = 1/110 (1 - 9 ln(1)) = 1 (1-0) = 1

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