Answer to Question #1478 in Molecular Physics | Thermodynamics for Rooky
According to the heat balance equation,
Cm1Δ T1 = Cm2Δ T2
Δ T1 = (T-20)
Δ T2 = (80-T)
200*(T-20) = 100* (80 - T)
2T-40 = 80 - T
3T = 120
T = 40 C.
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