Question #1453

2 litres of mercury at 80 deg.Celsius is pushed into a plastic bucket containing 10 litres of mercury at a temperature "T".if the final temperature of the mixture is 30 degree Celsius ,what is the value of "T".(neglect any heat loss to environment)

Expert's answer

We can use the heat balance equation

Cm m1 ΔT1 = Cm m2 ΔT2

ΔT1 = 80 - 30 =50

ΔT2 = 30 - T

m1/m2 = 2/10 = 0.2

Thus

(30-T) = 50*0.2 = 10

T = 30-10 = 20 C.

Answer:**T= 20 C.**

Cm m1 ΔT1 = Cm m2 ΔT2

ΔT1 = 80 - 30 =50

ΔT2 = 30 - T

m1/m2 = 2/10 = 0.2

Thus

(30-T) = 50*0.2 = 10

T = 30-10 = 20 C.

Answer:

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