# Answer to Question #1189 in Molecular Physics | Thermodynamics for queue tea

Question #1189

How can we evaluate the change in density between the given pressure when melting point of tin at pressure of 1 bar is 505K, but increases to 508.4K at 1000 bar?

please tel the steps and formulas used.

please tel the steps and formulas used.

Expert's answer

According the formula

PV/T = const

So, we get

103x10

But the mass of tin is const, so density is greater inV

V

Answer: it’s greater in 1.006*10

PV/T = const

So, we get

103x10

^{3}Pa *V_{1}/ 505K = 103x10^{6}Pa *V_{2}/ 508.4 KBut the mass of tin is const, so density is greater inV

_{1}/V_{2}.V

_{1}/V_{2}= 103,000/505 * 508.4 / 103,000,00 = 1.006*10^{-3}Answer: it’s greater in 1.006*10

^{-3}Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment