Answer to Question #1319 in Molecular Physics | Thermodynamics for Laine
Δ T = Q /(m*Cm)
Q = 75 cal= 313.8 J
m = 0.075 kg
Cm = 4.18 kJ/kg*grad
Δ T = Q /(m*Cm) = 313.8 / (0.075*4.18x103) = 1.
The temperature will increase by one Kelvin.
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!