Question #1319

How do i solve this problem using the thermodynamic structure? <br>- what will be the temperature change when 75 cal of heat are added to 75 g of water?

Expert's answer

It can be found using the formula:

Δ T = Q /(m*Cm)

Q = 75 cal= 313.8 J

m = 0.075 kg

Cm = 4.18 kJ/kg*grad

Δ T = Q /(m*Cm) = 313.8 / (0.075*4.18x103) = 1.

The temperature will increase by one Kelvin.

Δ T = Q /(m*Cm)

Q = 75 cal= 313.8 J

m = 0.075 kg

Cm = 4.18 kJ/kg*grad

Δ T = Q /(m*Cm) = 313.8 / (0.075*4.18x103) = 1.

The temperature will increase by one Kelvin.

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