Answer to Question #11377 in Electric Circuits for saksham
R1 = U1^2 /
P1 = 220^2 / 40 = 1210 Ohm
R2 = U2^2 / P2 = 220^2 / 100 = 484 Ohm
use P = I^2 * R for each bulb and find out if it is greater than
rating. The one with higher power rating will get fused.
P1 = (220 / (1210 +
484))^2 * 1210 = 20.408 W
P2 = (220 / (1210 + 484))^2 * 484 = 8.163
Answer: first bulb will glow brighter.
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