Answer to Question #11372 in Electric Circuits for saksham
As P1 = P2 = P3 = 1KW, the electric bulb has highest resistance (U3 > U2 = U1).
R3 = U^2 / P = 259^2 / 1000 = 67.081 Ohm.
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!