Answer to Question #11373 in Electric Circuits for saksham
R1 = U1^2 / P1 = 220^2 / 25 = 1936 Ohm
R2 = U2^2 / P2 = 220^2 / 100 = 484 Ohm
Let's use P = I^2 * R for each bulb and find out if it is greater than its power rating. The one with higher
power rating will get fused.
P1 = (440 / (1936 + 484))^2 * 1936 = 64 W
P2 = (440 / (1936 + 484))^2 * 484 = 16 W.
Answer: first bulb will get fused (64W > 25W).
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!