Question #11373

If two bulbs of wattages 25 W and 100 W respectively , each rated at 220 V are connected in series with the supply of 440 V, which bulb will get fused?

Expert's answer

Let's find out the resistances of each bulb from the data given:

R1 = U1^2 / P1 = 220^2 / 25 = 1936 Ohm

R2 = U2^2 / P2 = 220^2 / 100 = 484 Ohm

Let's use P = I^2 * R for each bulb and find out if it is greater than its power rating. The one with higher

power rating will get fused.

P1 = (440 / (1936 + 484))^2 * 1936 = 64 W

P2 = (440 / (1936 + 484))^2 * 484 = 16 W.

Answer: first bulb will get fused (64W > 25W).

R1 = U1^2 / P1 = 220^2 / 25 = 1936 Ohm

R2 = U2^2 / P2 = 220^2 / 100 = 484 Ohm

Let's use P = I^2 * R for each bulb and find out if it is greater than its power rating. The one with higher

power rating will get fused.

P1 = (440 / (1936 + 484))^2 * 1936 = 64 W

P2 = (440 / (1936 + 484))^2 * 484 = 16 W.

Answer: first bulb will get fused (64W > 25W).

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