Question #184245

A single-phase asymmetrical semi-converter feeds an R-L load with R=50 Î© and a large L= 10 mH so that load current is constant. The source voltage is 230 V, 50 Hz. For a firing angle of 600, determine: (i) Average value of output voltage and output current. (ii) Average and rms values of diode, thyristor and source currents.(iii) Input power factor.Â

Expert's answer

**i)Average value of output voltage and output current.**

"V_O=\\frac{v_m}{\\pi}=\\frac{230 \\sqrt{2}}{\\pi}(1+cos 60)=155.31V"

"I_o=\\frac{V_o}{R}=\\frac{155.31}{50}=3.11A"

**(ii) Average and rms values of diode, thyristor and source currents**.

"I_pavg=3.11\\times\\frac{\\pi-\\frac{\\pi}{3}}{2\\pi}=1.04A"

"I_DAvg=3.11\\times\\frac{\\pi+\\frac{\\pi}{3}}{2\\pi}=2.07A"

"I_Trms=3.11\\times\\sqrt{\\frac{\\pi-\\pi \/3}{2\\pi}}=1.79A"

"I_Drms=3.11\\times\\sqrt{\\frac{\\pi+\\pi \/3}{2\\pi}}=2.54A"

Source current "I_DAvg=3.11\\times\\frac{\\pi+\\frac{\\pi}{3}}{2\\pi}=2.07A"

"I_Drms=3.11\\times\\sqrt{\\frac{\\pi+\\pi \/3}{2\\pi}}=2.54A"

(iii) Input power factor.Â

"\\frac{I_{SI}}{I_{Sr}}cos\\frac{\\alpha}{2}=\\frac{2.42}{2.54}cos\\frac{60}{2}=0.825"

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