Question #183581

A capacitor consists of two similar square aluminium plates, each 10 cm × 10 cm mounted parallel and opposite to each other. What is their capacitance in μ F when distance between them is 1 cm and the dielectric is air

Expert's answer

The capacity of a flat capacitor is "C=\\cfrac{\\epsilon \\cdot\\epsilon_0 \\cdot S}{d}"

Where

"\\epsilon=1"

"\\epsilon_0=8.85 \\cdot 10^{-12} \\cfrac{F}{m}"

"S=0.1 \\cdot 0.1 m^2=1 \\cdot 10^{-2} m^2"

"d=1 \\cdot 10^{-2} m"

Then

"C=\\cfrac{1 \\cdot8.85 \\cdot 10^{-12} \\cdot 1 \\cdot 10^{-2}}{1 \\cdot 10^{-2}}=8.85 \\cdot 10^{-12}F=0.00885\\mu F"

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