56 208
Assignments Done
99,1%
Successfully Done
In January 2018
Your physics homework can be a real challenge, and the due date can be really close — feel free to use our assistance and get the desired result.
Be sure that math assignments completed by our experts will be error-free and done according to your instructions specified in the submitted order form.
Our experts will gladly share their knowledge and help you with programming homework. Keep up with the world’s newest programming trends.

Answer on Organic Chemistry Question for Sadaam Ahmed

Question #21147
What volume of 2.0 mol/L sulfuric acid will be exactly neutralized by 12.3 mL of 1.5 mol/L potassium hydroxide?
Expert's answer
c = n / V
The amount of potassium hydroxide in solution is
n(KOH) = c(KOH) * V(KOH solution) = 1.5 mol/L * 12.3 * 10^-3L = 18.45 * 10^-3 mol = 18.45 mmol

H2SO4 + 2KOH = K2SO4 + 2H2O

According to reaction above one mol of sulfuric acid reacts with two mol of potassium hydroxide. Thus, the amount of sulfuric acid is
n(H2SO4) = n(KOH) / 2 = 18.45 / 2 = 9.225 mmol
The volume of sulfuric acid solution is
V(H2SO4) = n(H2SO4) / c(H2SO4) = 9.225 * 10^-3 mol / 2.0 mol/L = 0.0046 L = 4.6 mL

Answer: 4.6 mL of 2.0 mol/L sulfuric acid will be exactly neutralized by 12.3 mL of 1.5 mol/L potassium hydroxide.

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

Assignment Expert
08.01.2013 08:09

You're welcome. We are glad to be helpful.
If you really liked our service please press like-button beside answer field. Thank you!

Sadaam Ahmed
29.12.2012 15:13

Thank you for answering my question!!!

Leave a comment

Ask Your question