# Answer to Question #21145 in Organic Chemistry for Sadaam Ahmed

Question #21145

What is the concentration of HCL, when 50.0 mL of the solution was neutralized by 12 mL of a 0.35 mol/L solution of KOH?

Expert's answer

For answering this question you need to use next law:

N

where N is normality (in this case it is the same that molaritiy) and V is volume,

So N

N

_{1}V_{1}= N_{2}V_{2},where N is normality (in this case it is the same that molaritiy) and V is volume,

So N

_{2}= N_{1}V_{1}/V_{2}= 12*0.35 / 50.0 = 0.084 mol/lNeed a fast expert's response?

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