Answer to Question #21143 in Organic Chemistry for Sadaam Ahmed

Question #21143
125 g of lithium metal reacts with 3.0 L of 2.5 mol/L sulfuric acid solution. a)Calculate the mass of lithium remaining after the reaction is over. b) Calculate the volume of hydrogen gas produced, if this reaction occurs at STP.
Expert's answer
2Li + H2SO4 = Li2SO4 + H2

First seek theamount of substance for the lithium and sulfuric acid:
n(Li) = 125/7 = 17.857 mol
n(H2SO4) = 3 x 2.5 = 7.5 mol

Next seek the amount ofsubstance lithium remaining after the reaction is over:
n(Li) = 17.857 - 15 = 2.857 remaining after the reaction is over.

Тhe amount of substance ofhydrogen will be:
n(H2) = n(H2SO4) = 15 mol
V(H2) = n(H2) x Vm(H2)
V(H2) = 15 mol x 22.4 mol/l = 336 liters

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