Answer to Question #4253 in Inorganic Chemistry for Amanda Joncas
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thank you so much for your help! unfortunatley, i no longer need the help with this problem because I already turned in the assignment seeing as this question was asked over a month ago. i appreciate your time, though.
First you balance the equation
10 KClO3+ 3 P4 --> 3 P4O10 + 10 KCl
Then you convert 52.9 g KClO3 to moles by multiplying it by (1 mole KClO3 / 122.55 g/mol) = .431 mol KClO3
Multiple by mole ratio : .431 mol KClO3 x (3/10)= .129 mol P4O10 produced
Convert to grams
.129 x 284 g/mol= 36.63 g of P4O10