Answer to Question #4235 in Inorganic Chemistry for lory joy
What is the % of oxygen in the compound?
m(oxide) = 3.45g
m(O) = m(oxide) -m(Mg) = 3.45 - 1.25 = 2.2 g
w(O) = m(O)/m(oxide)*100% = 2.2/3.45*100% = 63.77%
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