Question #4161

Calculate the volume occupied at 0 degree Celsius by 100g of liquid water & by 100g of Ice?&

Calculate the percentage increased in volume when 100g of water freezes at 0 degree Celsius?&

Calculate the concentration of water (in M) at 0 degree Celsius?

Calculate the percentage increased in volume when 100g of water freezes at 0 degree Celsius?&

Calculate the concentration of water (in M) at 0 degree Celsius?

Expert's answer

Calculate the volume occupied at 0 degree Celsius by 100g of liquid water

& by 100g of Ice?

Calculate the percentage increased in volume when 100g of water freezes at

0 degree Celsius?

Calculate the concentration of water (in M) at 0 degree Celsius?

The density of liquid water at 0 degree Celsius is 1 g/ml. So, the volume of 100g liquid water at 0 degree Celsius is 100ml.

The density of ice is 0,9 g/ml. So, the volume of 100g of ice is (100g)/(0.9g/ml) = 111ml.

The percentage increased in volume when 100g of water freezes at 0 degree Celsius is (111ml/100ml)*100% = 111%.

Let`s calculate the concentration of water at 0 degree Celsius.

M(H2O) = 2M(H) +M(O) = 2·1+16 = 18 (g/mol)

(100g)/(18g/mol) = 5.55 mol

So, the concentration of water at 0 degree Celsius is (5.55mol)/(100ml) = 0.0555 mol/ml.

& by 100g of Ice?

Calculate the percentage increased in volume when 100g of water freezes at

0 degree Celsius?

Calculate the concentration of water (in M) at 0 degree Celsius?

The density of liquid water at 0 degree Celsius is 1 g/ml. So, the volume of 100g liquid water at 0 degree Celsius is 100ml.

The density of ice is 0,9 g/ml. So, the volume of 100g of ice is (100g)/(0.9g/ml) = 111ml.

The percentage increased in volume when 100g of water freezes at 0 degree Celsius is (111ml/100ml)*100% = 111%.

Let`s calculate the concentration of water at 0 degree Celsius.

M(H2O) = 2M(H) +M(O) = 2·1+16 = 18 (g/mol)

(100g)/(18g/mol) = 5.55 mol

So, the concentration of water at 0 degree Celsius is (5.55mol)/(100ml) = 0.0555 mol/ml.

## Comments

## Leave a comment