Question #171469

**An x-ray has a wavelength of 4.40 Å. Calculate the energy (in J) of one photon of this radiation. Enter your answer in scientific notation.**

Expert's answer

Let Energy in J be...... E(J)

"E(J)=h(j.s)\u00d7v(Hz)"

Where "v(Hz)=\\frac{C(m\/s)}{\\lambda(m)}"

h = Planck's constant "6.63\u00d710^{-34}J.s"

C= Speed of light "3.00\u00d710^{8}m\/s"

Convert the wavelength from Angstrom **Å **to meter (m) "4.40 \u00d7 \\frac{1}{10^{10}}" = "4.40\u00d710^{-10}"

Therefore

"E(J) = 6.63\u00d710^{-34}(\\frac{3.00\u00d710^8}{4.40\u00d710^{-10}})"

"E(J) = 4.52\u00d710^{-16}"

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