Question #171465

How many millimoles of NaOH contain 5.63 x 10^22 formula units of NaOH

Expert's answer

1 mole of NaOH would have "6.02 \u00d710^{23}" (avogadro's constant)

Molar mass of NaOH = 40

Hence

"5.63\u00d710^{22}"** **formula units of NaOH will have mass:

"(\\frac{40}{6.02\u00d710^{23}} ) 5.63 \u00d710^{22} = 3.74g"

In millimoles = "\\frac{3.74}{1000}= 0.00374 millimoles"

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