Question

A sample of B₂H₆ gas in a 35.0-mL container is at a pressure of 450. mm Hg and a temperature of 571 °C. If the gas is allowed to cool at constant volume until the pressure is 354 mm Hg, what is the new temperature in °C?

Answer 1

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

=$\frac{450}{844}=\frac{354}{T_2}$

=$T_2=\frac{844×354}{450}$ =663.95K

$T_2=390.95^{o}C$