Question #171464

Calculate the mass in grams of 6.71 x 10^25 molecules of water

Expert's answer

1 mole of water would have "6.02 \u00d710^{23}" (avogadro's constant)

Molar mass of water = 1(2)+16 = 18

Hence

"6.71\u00d710^{25}"** **molecules of water would have a mass of:

"(\\frac{18}{6.02\u00d710^{23}} ) 6.71 \u00d710^{25} = 2006.3 g"

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