Question #68927

a mixture of C2H2 and C3H8 is covered a certain volume at 80mmHg.mixture burn and make CO2 and H2O.if the pressure of CO2 is found 230mmHg at equal temperature and volume?

Expert's answer

C_2 H_2+(2+2/4) O_2→2CO_2+H_2 O

C_3 H_8+(3+8/4) O_2→3CO_2+4H_2 O

x+y=80

2x+3y=230

2(80-y)+3y=230

y=70.

The fraction of C3H8 in the mixture is

70/80 100%=87.5%.

C_3 H_8+(3+8/4) O_2→3CO_2+4H_2 O

x+y=80

2x+3y=230

2(80-y)+3y=230

y=70.

The fraction of C3H8 in the mixture is

70/80 100%=87.5%.

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