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Answer to Question #68923 in Molecular Physics | Thermodynamics for DEEPENDRA SINGH

Question #68923
a pure gass which contains 14.3% hydrogen and 85.7% carbon of total mass.its density is 2.5 gram per leter at 0 degree centigrate and 1 atm.what is it molecular formula?
Expert's answer
From the equation of state for perfect gas
We obtain the expression for the density of gas
Therefore the molar mass of gas is
M=ρRT/P=(2.5×8.3×273)/(1.01×〖10〗^5 )=56 g/mol.
M(H)=1 g/mol,M(C)=12 g/mol.
We obtain
So the number of hydrogen atoms is twice of carbon.
Because the molar mass of gas is 56, we obtain equation for the number of carbon atoms x
2×1×x+12×x=56 ⇒ x=4.
So the molecular formula of the gas is
C_4 H_8
Answers: C_4 H_8

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