At a party 0.50 kg tube ice at -10 degrees C is placed in 3.0 kg of iced tea at 20 degrees C . At what temperature will be the final mixture be?The tea can be considered as water.Assume a heat flow sorroundings and the container.
Heat gain = Heat loss
The heat offusion of water ice is 334 kJ/kg. Ice heat capacity is 2.11 kJ / (kg * K) Water heat capacity (for temperature above zero) is 4.1813 kJ / (kg * K).
Let's assume the final mixture is totally liquid at temperature T above zero in Celsius scale. Then the heat balance equation is