Answer to Question #9774 in Mechanics | Relativity for yelona
Let's find the time of flight
mv2/2=mgh => h=v2/2g
Also we can write that h=gt^2/2 whence t=sqrt(2h/g)
So the total time of flight T=2sqrt(2h/g)=2sqrt(2v^2/2g^2)=2v/g=2*20/10=4s
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