# Answer to Question #9696 in Mechanics | Relativity for Elly M De La Cruz

Question #9696

College softball distance from the pitcher's mound to the batter is 43 feet. If the ball leaves the bat at 85 mph, how much time elapses between the hit and the ball reaching the pitcher?

Expert's answer

1 Mile = 5280 Feet

So, the time which elapses between the hit and the ball

reaching the pitcher:

t = d / v = 43 / (85 * 5280) = 43 / 448800 hrs

To

get the answer in seconds, we should multiply it by 60 * 60 = 3600.

t = 3600

* 43 / 448800 = 0.344919786 = approx. 0.345 seconds.

So, the time which elapses between the hit and the ball

reaching the pitcher:

t = d / v = 43 / (85 * 5280) = 43 / 448800 hrs

To

get the answer in seconds, we should multiply it by 60 * 60 = 3600.

t = 3600

* 43 / 448800 = 0.344919786 = approx. 0.345 seconds.

## Comments

## Leave a comment